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对于微信小程序MD5的方法的解析

时间:2023/12/21作者:未知来源:争怎路由网人气:

(~d)), a, b, x, s, t) } /* * Calculate the MD5 of an array of little-endian words, producing an array * of little-endian words. */ function coreMD5(x) { var a = 1732584193 var b = -271733879 var c = -1732584194 var d = 271733878 for(var i = 0; i < x.length; i += 16) { var olda = a var oldb = b var oldc = c var oldd = d a = ff(a, b, c, d, x[i+ 0], 7 , -680876936) d = ff(d, a, b, c, x[i+ 1], 12, -389564586) c = ff(c, d, a, b, x[i+ 2], 17, 606105819) b = ff(b, c, d, a, x[i+ 3], 22, -1044525330) a = ff(a, b, c, d, x[i+ 4], 7 , -176418897) d = ff(d, a, b, c, x[i+ 5], 12, 1200080426) c = ff(c, d, a, b, x[i+ 6], 17, -1473231341) b = ff(b, c, d, a, x[i+ 7], 22, -45705983) a = ff(a, b, c, d, x[i+ 8], 7 , 1770035416) d = ff(d, a, b, c, x[i+ 9], 12, -1958414417) c = ff(c, d, a, b, x[i+10], 17, -42063) b = ff(b, c, d, a, x[i+11], 22, -1990404162) a = ff(a, b, c, d, x[i+12], 7 , 1804603682) d = ff(d, a, b, c, x[i+13], 12, -40341101) c = ff(c, d, a, b, x[i+14], 17, -1502002290) b = ff(b, c, d, a, x[i+15], 22, 1236535329) a = gg(a, b, c, d, x[i+ 1], 5 , -165796510) d = gg(d, a, b, c, x[i+ 6], 9 , -1069501632) c = gg(c, d, a, b, x[i+11], 14, 643717713) b = gg(b, c, d, a, x[i+ 0], 20, -373897302) a = gg(a, b, c, d, x[i+ 5], 5 , -701558691) d = gg(d, a, b, c, x[i+10], 9 , 38016083) c = gg(c, d, a, b, x[i+15], 14, -660478335) b = gg(b, c, d, a, x[i+ 4], 20, -405537848) a = gg(a, b, c, d, x[i+ 9], 5 , 568446438) d = gg(d, a, b, c, x[i+14], 9 , -1019803690) c = gg(c, d, a, b, x[i+ 3], 14, -187363961) b = gg(b, c, d, a, x[i+ 8], 20, 1163531501) a = gg(a, b, c, d, x[i+13], 5 , -1444681467) d = gg(d, a, b, c, x[i+ 2], 9 , -51403784) c = gg(c, d, a, b, x[i+ 7], 14, 1735328473) b = gg(b, c, d, a, x[i+12], 20, -1926607734) a = hh(a, b, c, d, x[i+ 5], 4 , -378558) d = hh(d, a, b, c, x[i+ 8], 11, -2022574463) c = hh(c, d, a, b, x[i+11], 16, 1839030562) b = hh(b, c, d, a, x[i+14], 23, -35309556) a = hh(a, b, c, d, x[i+ 1], 4 , -1530992060) d = hh(d, a, b, c, x[i+ 4], 11, 1272893353) c = hh(c, d, a, b, x[i+ 7], 16, -155497632) b = hh(b, c, d, a, x[i+10], 23, -1094730640) a = hh(a, b, c, d, x[i+13], 4 , 681279174) d = hh(d, a, b, c, x[i+ 0], 11, -358537222) c = hh(c, d, a, b, x[i+ 3], 16, -722521979) b = hh(b, c, d, a, x[i+ 6], 23, 76029189) a = hh(a, b, c, d, x[i+ 9], 4 , -640364487) d = hh(d, a, b, c, x[i+12], 11, -421815835) c = hh(c, d, a, b, x[i+15], 16, 530742520) b = hh(b, c, d, a, x[i+ 2], 23, -995338651) a = ii(a, b, c, d, x[i+ 0], 6 , -198630844) d = ii(d, a, b, c, x[i+ 7], 10, 1126891415) c = ii(c, d, a, b, x[i+14], 15, -1416354905) b = ii(b, c, d, a, x[i+ 5], 21, -57434055) a = ii(a, b, c, d, x[i+12], 6 , 1700485571) d = ii(d, a, b, c, x[i+ 3], 10, -1894986606) c = ii(c, d, a, b, x[i+10], 15, -1051523) b = ii(b, c, d, a, x[i+ 1], 21, -2054922799) a = ii(a, b, c, d, x[i+ 8], 6 , 1873313359) d = ii(d, a, b, c, x[i+15], 10, -30611744) c = ii(c, d, a, b, x[i+ 6], 15, -1560198380) b = ii(b, c, d, a, x[i+13], 21, 1309151649) a = ii(a, b, c, d, x[i+ 4], 6 , -145523070) d = ii(d, a, b, c, x[i+11], 10, -1120210379) c = ii(c, d, a, b, x[i+ 2], 15, 718787259) b = ii(b, c, d, a, x[i+ 9], 21, -343485551) a = safe_add(a, olda) b = safe_add(b, oldb) c = safe_add(c, oldc) d = safe_add(d, oldd) } return [a, b, c, d] } /* * Convert an array of little-endian words to a hex string. */ function binl2hex(binarray) { var hex_tab = "0123456789abcdef" var str = "" for(var i = 0; i < binarray.length * 4; i++) { str += hex_tab.charAt((binarray[i>>2] >> ((i%4)*8+4)) & 0xF) + hex_tab.charAt((binarray[i>>2] >> ((i%4)*8)) & 0xF) } return str } /* * Convert an array of little-endian words to a base64 encoded string. */ function binl2b64(binarray) { var tab = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" var str = "" for(var i = 0; i < binarray.length * 32; i += 6) { str += tab.charAt(((binarray[i>>5] << (i%32)) & 0x3F)

关键词:对于微信小程序MD5的办法的解析




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